the ratio of present ages of a lady and her daughter is 5:3. 9 years ago mother's age was double the age of the daughter. find their present ages
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Let the present ages of mother and daughter be x and y respectively.
Given x : y = 5 : 3 ⇒ y = 3x/5
Age of mother 9 years ago = x-9
Age of daughter 9 years ago = y - 9
Given x - 9 = 2(y - 9)
⇒ 9 = 2y -x = 6x/5 - x = x/5
So, x/5 = 9 ⇒ x = 45
y = 3x/5 = 27
So, the present age of mother is 45 years and the present age of daughter is 27 years
Given x : y = 5 : 3 ⇒ y = 3x/5
Age of mother 9 years ago = x-9
Age of daughter 9 years ago = y - 9
Given x - 9 = 2(y - 9)
⇒ 9 = 2y -x = 6x/5 - x = x/5
So, x/5 = 9 ⇒ x = 45
y = 3x/5 = 27
So, the present age of mother is 45 years and the present age of daughter is 27 years
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hence , present age of mother= 45 years
and present age of daughter= 27years
hope it helps.....
if my answer is helpful please mark it as brainliest...
and present age of daughter= 27years
hope it helps.....
if my answer is helpful please mark it as brainliest...
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