Question

The ratio of present ages of Albert and Salim are In the ratio 5:9.Five years hence the ratio of their ages will 3:5.Find their present ages.

Answer 1

❣$\boxed{Heya\:There}$❣

➡️✒$\underline{QUESTION:-}$

The ratio of present ages of Albert and Salim are in the ratio 5:9. Five years hence the ratio of their ages will 3:5. Find their present ages.

➡️✒$\underline{ANSWER:-}$

Let,
The present age of Albert = 5x
And the present age of Salim = 9x

A. T. Q

5x+5/9x+5 = 3/5
5(5x+5) = 3(9x+5)
25x + 25 = 27x + 15
25x - 27x = 15 - 25
-2x = -10
x = 10/2
x = 5

Hence, the age of Albert = 5x
= 5 × 5
= 25 years

the age of Salim = 9x
= 9 × 5
= 45 years


# BE BRAINLY ☺☺

Answer 2

Answer:
_______________________________

The ratio of present ages of Albert and Salim is 5:9.

$let \: x \: be \: the \: common \: multiple \: of \: this \: ratio \:$
Then their present ages are 5x years and 9x years respectively.

After five years,

$Albert's \: ags = (5x + 5)years \\ \\ Salim's \: age \: = (9x + 5)years$
__________________________

According to the given condition,

$\frac{5x + 5}{9 x + 5} = \frac{3}{5} \\ \\ 5(5x + 5) = 3(9x + 5).......(cross \: multiplying \: the \: terms) \\ \\ 25x + 25 = 27x + 15 \\ \\ 25 - 15 = 27x - 25x.........(bringing \: the \: terms \: with \: x \: together \: and \: numbers \: together) \\ \\ 10 = 2x.......(subtracting \: the \: terms \\ \\ x = \frac{10}{2} ........(dividing \: 10 \: by \: 2 \: to \: find \: the \: value \: of \: x \: in \: the \: ratio) \\ \\x = 5.$
_________________________
$Albert's \: age = 5x = 5 \times \times 5 = 25years \\ \\ Salim's \: age = 9x = 9 \times 5 = 45years$