Question

The ratio of present ages of Albert and salim is 5:9. Five years hence ratio of their ages will be 3 : 5. Find their present ages.

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Answer 1

Answer:

$\huge \dag \sf \red{question}$

The ratio of present ages of Albert and salim is 5:9. Five years hence ratio of their ages will be 3 : 5. Find their present ages.

$\huge \sf \blue{answer} \downarrow$

ratio of their ages is 3:5

Let the common multiple be x

Present age of Salim = 9x

Present age of Albert= 5x

After 5 years,

Albert's age= (5x+5) years

Salim's age= (9x+5)

So their ratio after 5 years 3:5

$\frac{5x + 5}{9x + 5} = \frac{3}{5}$

$\therefore \: 5(5x + 5) = 3(9x + 5) \\ \\ 25x + 25 = 27x + 15 \\ \\ 25 - 15 = 27x + 25 \\ \\ 10 = 2x \\ \\ \therefore \: x = \frac{ { \cancel{10}} \: \: ^{5} }{ \cancel2} \\ \\ x = 5$

So

Present age of Albert= 5x=5×5=25 years

Present age of Salim = 9x=9×5=45 years

Hope it helps you from my side

:)

Answer 2

Answer:

Let present ages of Albert & Salim be x, y

⇒

y

x

=

9

5

⇒x=

9

5y

and

y+5

x+5

=

5

3

⇒5x+25=3y+15

⇒5(

9

5y

)=3y−10

⇒25y=27y−90

⇒2y=90

⇒y=45

⇒x=

9

5

(45)

=5×5=25.

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