Question

The ratio of present ages of Mohit and Mayank in 11:8. After 8 years, the ratio of their ages wille be 5:4 fin​d their present age

Answer 1

Answer:

let the present age of mohit be 11x

let the present age of mayank be 8x

after 8 years

mohit=11x+8

mayank=8x+8

11x+8/8x+8= 5/4

now we will do cross multiplication

4(11x+8)= 5(8x+8)

44x+32= 40x+40

44x-40x= 40-32

4x= 8

x=8/4

x= 2

Answer 2

Answer:

Lat Mayank's age be 11x

Let Mohit's age be 8x

Therefore

$\frac{11x + 8}{8x + 8} = \frac{5}{4} \\ = > 44x + 32 = 40x + 40 \\ = > 44x - 40x = 40 - 32 \\ = > 4 x= 8 \\ = > x = \frac{8}{4} \\ x = 2$

So Mohit = 2 × 11 = 22 yrs

Mayank = 8 × 2 = 16 yrs