Math, asked by asdfqwert2560, 10 months ago

The ratio of present ages of two brothers is 1 : 2 and 5 years back, the ratio was of their ages was 1:3.What will be the ratio of their ages after 5 years?

Answers

Answered by ArshadNadeem
7

Answer:

3:5 hope it helps .

Mark as brainliest

Answered by itzsecretagent
110

\Huge \underline{\mathcal \pink{A}\purple{\frak{nSwer}}}

❍ Given that, the ratio of present ages of two brothers is 1: 2. So, let's say that the present ages of the two brothers be x and 2x respectively.

⭒ By Given C O N D I T I O N :

Five years back, the ratio of their ages (both brother's ages) was 1: 3.

Therefore,

☆ Five years ago their ages —

Younger brother = (x – 5)

Elder brother = (2x – 5)

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Now,

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\begin{gathered}\dashrightarrow\sf \bigg\{\dfrac{x - 5}{2x - 5}\bigg\} = \bigg\{\dfrac{1}{3}\bigg \} \\ \\\\\dashrightarrow\sf 3\Big\{x - 5\Big\} = \Big\{2x - 5\Big\} \\ \\ \ \\\dashrightarrow\sf 3x - 15 = 2x - 5\\\ \\ \\\dashrightarrow\sf 3x - 2x = - 5 + 15\\\ \\ \ \\\dashrightarrow\underline{\boxed{\frak{\pmb{\pink{x = 10 }}}}}\;\bigstar\end{gathered}

Hence,

Present ages of both brother are, x = 10 years

2x = 2(10) = 20 years

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\therefore{\underline{\textsf{Present~ages~of~two~brothers~are~\textbf{10 years and 20 years}.}}}

\rule{300px}{.3ex}

R A T I O :

After five years the ratio their ages will be —

\begin{gathered}:\implies\sf \dfrac{10 + 5}{20 + 5} \\\\\\:\implies\sf \cancel\dfrac{15}{25} \\ \\ \\:\implies{\boxed{\underline{\frak{\purple{\dfrac{3}{5}}}}}}\;\bigstar\end{gathered}

\therefore{\underline{\textsf{Hence,~the~required~ratio~of~their~ages~is~ \textbf{3:5}.}}}

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