the ratio of present ages of two brothers is 1:2 and 5 years back the ratio was 1:3. what will be the ratio of their ages after 5 years ?
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Answered by
185
given ratio of present age= 1:2
let ages be x,2x
5yrs back ratio was 1:3
so 5yrs back ages be x-5/2x-5 = y/3y
so after 5 yrs ages are x+5/2x+5
by solving we get 1st age = 10yrs ,2nd age = 20yrs.
so after 5yrs ratio = x+5/2x+5 = 15/25 = 3/5 = 3:5
let ages be x,2x
5yrs back ratio was 1:3
so 5yrs back ages be x-5/2x-5 = y/3y
so after 5 yrs ages are x+5/2x+5
by solving we get 1st age = 10yrs ,2nd age = 20yrs.
so after 5yrs ratio = x+5/2x+5 = 15/25 = 3/5 = 3:5
HargunKaurPannu:
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Answered by
169
Hi !
Let their present ages be x and 2x
The ratio of their ages five years before is 1/3
their ages 5 yrs before are x -5 and 2x - 5
i.e.,
x-5/2x- 5 = 1/3
cross multiply ,
2x - 5 = 3x - 15
x = 10
2x = 20
their present ages are 10 and 20 respectively.
Their ages 5 years later are 15 and 25 years.
Ratio of ages 5 yrs later = 15/25 = 3/5 = 3:5
Hope this Helps You !
Let their present ages be x and 2x
The ratio of their ages five years before is 1/3
their ages 5 yrs before are x -5 and 2x - 5
i.e.,
x-5/2x- 5 = 1/3
cross multiply ,
2x - 5 = 3x - 15
x = 10
2x = 20
their present ages are 10 and 20 respectively.
Their ages 5 years later are 15 and 25 years.
Ratio of ages 5 yrs later = 15/25 = 3/5 = 3:5
Hope this Helps You !
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