the ratio of pure milk of water in a can of adulterated milk is 8:1.if the pure milk is 96kg,how much water has been mixed with it?
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let the concentration water=x
the concentration of pure milk=8x
According to question
8x=96
x=96÷8
x=12
the concentration of pure milk=8x
According to question
8x=96
x=96÷8
x=12
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