The ratio of raddi of second orbits of
He,Li and Be is:
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1
Answer:
Explanation:
The ratio of the radius of two Bohr's orbit of Li^(+2) is 1:9.
Since radius is directly proportional to the square of 'n',
radius of2 nd Bohr orbit /radius of1 st Bohr orbit =0.529 /0.529 *2^2/1 = 4
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radius of nth orbit of an atom is o.52 n^2/z(A)
n --->orbit number,
z--->atomic number
ratio of n^2/a of He:Li:Be
4/2:4/3:4/4=6:4:3
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