Chemistry, asked by pp992539, 6 months ago

The ratio of raddi of second orbits of
He,Li and Be is:​

Answers

Answered by sinhanidhi716
1

Answer:

Explanation:

The ratio of the radius of two Bohr's orbit of Li^(+2) is 1:9.

Since radius is directly proportional to the square of 'n',

radius of2  nd Bohr orbit /radius of1 st Bohr orbit =0.529 /0.529 *2^2/1 = 4

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Answered by goud22277
0

radius of nth orbit of an atom is o.52 n^2/z(A)

n --->orbit number,

z--->atomic number

ratio of n^2/a of He:Li:Be

4/2:4/3:4/4=6:4:3

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