Question

The ratio of radii of nuclei 13Al27 and 52Te125 is approximately- Options= 6:10 or 13:52 or 40:177 or 14:7

Answer 1

ratio of radii of nuclei is 6 : 10

Remember: radius of nuclei is directly proportional to cube root of its atomic mass number. i.e., R ∝ A⅓

from symbol of aluminium and Tellurium,

atomic mass number of Al = 27

and atomic mass number of Te, = 125

so, R1/R2= A1⅓/A2⅓ = (A1/A2)⅓

⇒R1/R2 = (27/125)⅓ = 3/5 = (3 × 2)/(5 × 2) = 6/10

so, option (1) 6 : 10 is correct choice.

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Answer 2

$\huge\bold\purple{Answer:-}$

radius of nuclei is directly proportional to cube root of its atomic mass number. i.e., R ∝ A⅓

from symbol of aluminium and Tellurium,

atomic mass number of Al = 27

and atomic mass number of Te, = 125

so, R1/R2= A1⅓/A2⅓ = (A1/A2)⅓

⇒R1/R2 = (27/125)⅓ = 3/5 = (3 × 2)/(5 × 2) = 6/10

so, option (1) 6 : 10 is correct choice.