the ratio of Rates of diffusion of two gases a and b is 1.5 ratio 1 if their relative molecular mass of a gas a is 16 find out the relative molecular mass of gas b
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Explanation:
It can be given by Graham's law of effusion or diffusion .
By the law
Rate of diffusion of gases is inversely proportional to the root of their densities
(D1/D2)^1÷2= R2/R1
Since D=m/v
m- molar mass of gas. ,v - volume
D1&D2 -density
R1 &R2- diffusion rates
For same volume ,
R1/R2 = (m2/m1)^1÷2
(1/5 )^2= m2/16
16/25 =m2
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