The ratio of respective kinetic energy of molecule of neon and nitrogen gas at 127°C is
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KE2KE1=n2T2n1T1
Let weight of niitrogen gas be 7x and that of oxygen gas be 8x
no. of moles of nitrogen = n1=287x
no. of moles of oxygen = n2=328x
Thus, at same temperature
KE2KE1=8x×287x×32=1:1
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