The ratio of rotational and translatory kinetic energies of a
sphere is
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An object is rotating without slipping. What percentage of its total kinetic energy is its translational kinetric energy if the object is a uniform sphere?
So this would be KrotationalKtrans
so for a solid sphere the moment of inertia is .5MR^225MR2 so this gives me \(\displaystyle \frac{\frac{1}{2}I_{cm}\omega^2}{\frac{1}{2}Mv_{cm}^2\) so this boils down to (1/10)/(1/2). The answer is 71.4% and I keep getting 20%
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