Math, asked by sd9074590, 4 months ago

The ratio of sand and cement in a mixture is 7:1 how much cement should be mixture in the remaining 72 kg of this mixture, so that the resulting mixture has a ratio of 6:1? ​

Answers

Answered by diyabhana
0

Answer:

the sane to cement ratio is now 63 / 10.5 = 6 / 1. So, we have 72 kg of the mixture containing sand and cement in the ratio 7:1. It means that there are 7+1 = 8 parts of the equal mass; each mass is = 9 kilograms. So, there are 7*9 = 63 kilograms of the sand and 9 kilograms of the cement in the original mixture.

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