Question

the ratio of side of triangle are 12 ratio 27 ratio 25 if the perimeter of the triangle is 540 cm find the length of sides​

Answer 1

Kindly Refer to the given figure Attached ^^""

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$\huge\mathbb{\underline{QUESTION:-}}$

★ the ratio of side of triangle are 12 ratio 27 ratio 25 if the perimeter of the triangle is 540 cm find the length of sides .

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$\huge\mathbb{\underline{SOLUTION:-}}$

★ Ratio of the sides of the triangle = 12 : 17 : 25

Let the common ratio be x then sides are 12x, 17x and 25x

★ Perimeter of the triangle = 540cm

• 12x + 17x + 25x = 540 cm

⇒ 54x = 540cm

⇒ x = 10

• Sides of triangle are,

★ 12x = 12 × 10 = 120cm

★ 17x = 17 × 10 = 170cm

★ 25x = 25 × 10 = 250cm

• Semi perimeter of triangle(s) = 540/2 = 270cm [ Using heron's formula ]

• Area of the triangle = √s (s-a) (s-b) (s-c)                                       

= √270(270 - 120) (270 - 170) (270 -250) cm2                                     

 = √270 × 150 × 100 × 20 cm 2                                   

   = 9000 cm2

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Answer 2

Kindly Refer to the given figure Attached ^^""

______________________________________

QUESTION:-

★ the ratio of side of triangle are 12 ratio 27 ratio 25 if the perimeter of the triangle is 540 cm find the length of sides .

________________________________________________

SOLUTION:-

★ Ratio of the sides of the triangle = 12 : 17 : 25

Let the common ratio be x then sides are 12x, 17x and 25x

★ Perimeter of the triangle = 540cm

12x + 17x + 25x = 540 cm

⇒ 54x = 540cm

⇒ x = 10

Sides of triangle are,

★ 12x = 12 × 10 = 120cm

★ 17x = 17 × 10 = 170cm

★ 25x = 25 × 10 = 250cm

Semi perimeter of triangle(s) = 540/2 = 270cm [ Using heron's formula ]

Area of the triangle = √s (s-a) (s-b) (s-c)                                      

= √270(270 - 120) (270 - 170) (270 -250) cm2                                    

= √270 × 150 × 100 × 20 cm 2                                  

  = 9000 cm2