Math, asked by palaksingh489, 8 months ago

the ratio of side of triangle are 12 ratio 27 ratio 25 if the perimeter of the triangle is 540 cm find the length of sides

Answers

Answered by Anonymous

Kindly Refer to the given figure Attached ^^""

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$\huge\mathbb{\underline{QUESTION:-}}$

★ the ratio of side of triangle are 12 ratio 27 ratio 25 if the perimeter of the triangle is 540 cm find the length of sides .

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$\huge\mathbb{\underline{SOLUTION:-}}$

★ Ratio of the sides of the triangle = 12 : 17 : 25

Let the common ratio be x then sides are 12x, 17x and 25x

★ Perimeter of the triangle = 540cm

12x + 17x + 25x = 540 cm

⇒ 54x = 540cm

⇒ x = 10

Sides of triangle are,

★ 12x = 12 × 10 = 120cm

★ 17x = 17 × 10 = 170cm

★ 25x = 25 × 10 = 250cm

Semi perimeter of triangle(s) = 540/2 = 270cm [ Using heron's formula ]

Area of the triangle = √s (s-a) (s-b) (s-c)

= √270(270 - 120) (270 - 170) (270 -250) cm2

= √270 × 150 × 100 × 20 cm 2

= 9000 cm2

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Attachments:

Answered by Anonymous

Kindly Refer to the given figure Attached ^^""

______________________________________

QUESTION:-

★ the ratio of side of triangle are 12 ratio 27 ratio 25 if the perimeter of the triangle is 540 cm find the length of sides .

________________________________________________

SOLUTION:-

★ Ratio of the sides of the triangle = 12 : 17 : 25

Let the common ratio be x then sides are 12x, 17x and 25x

★ Perimeter of the triangle = 540cm

12x + 17x + 25x = 540 cm

⇒ 54x = 540cm

⇒ x = 10

Sides of triangle are,

★ 12x = 12 × 10 = 120cm

★ 17x = 17 × 10 = 170cm

★ 25x = 25 × 10 = 250cm

Semi perimeter of triangle(s) = 540/2 = 270cm [ Using heron's formula ]

Area of the triangle = √s (s-a) (s-b) (s-c)