Question

The ratio of sides of a triangle 3:4:5 if area of the triangle is 72 sq units then the length of the smallest side is

Answer 1

Let the sides be 3x,4x,5x..

Steps in attachment.

Answer 2

Length of smallest side = 432 units.

Step-by-step explanation:

Since we have given that

Ratio of sides of a triangle = 3:4:5

Area of triangle = 72 sq. units

Since it is a right angled triangle.

$\dfrac{1}{2}\times 3x\times 4x=72\\\\\dfrac{12x^2}{2}=72\\\\6x^2=72\\\\x^2=\dfrac{72}{6}\\\\x^2=12\\\\x=144\ units$

Length of smallest side would be $144\times 3=432\ units$

Hence, length of smallest side = 432 units.

The length of sides of a triangle are in ratio 3:4:5.find the area of the triangle if its perimeter is 144 sq cm

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