Question

The ratio of sides of two similar triangles is a : B what is the ratio of their perimeters

Answer 1

Answer:

If a,c,e are the sides of one triangle with b,d,f as the corresponding sides of a triangle similar to the first the we know a/b = c/d = e/f. From the theorem on proportion, each ratio = (a+c+e)/(b+d+f) = Perimeter of the first triangle/perimeter of the second.

Answer 2

The ratio of their perimeters would be a:b.

Step-by-step explanation:

Since we have given that

Ratio of sides of two similar triangles = a:b

So, the perimeter of two similar triangles would be

$\dfrac{\text{Perimeter of first triangle}}{\text{Perimeter of second triangle}}=\dfrac{a}{b}$

Hence, the ratio of their perimeters would be a:b.

# learn more:

B) prove that the ratio of the areas of two similar triangle is equal to the ratio of the square of

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