Question

The ratio of slopes of logP Vs logV for reversible adiabatic process and reversible isothermal process of an ideal gas is equal to

Answer 1

Answer:

So, the ratio of adiabatic slope to isothermal slope is Y

Answer 2

Concept:

A thermodynamic process known as an adiabatic process (Q = 0) occurs when there is no heat transfer into or out of the system.

A thermodynamic process known as an isothermal process keeps the system's temperature constant.

Given:

log P vs log V for reversible adiabatic process and reversible isothermal process of an ideal gas.

Find:

The ratio of slopes of log P Vs log V for reversible adiabatic process and reversible isothermal process of an ideal gas is equal to?

Solution:

We know that the ideal gas equation can be expressed as:

                                        PV = RT

(PV)^γ = constant for the adiabatic expansion process.

PV = constant for isothermal expansion process.

Therefore,

                  log P = -γlogV ; slope = -γ

                  log P = -log V ; slope = -1

Thus, logP = γlogV

$\frac{log P}{log V}$ = γ

Hence, the ratio of slopes of log P Vs log V for reversible adiabatic process and reversible isothermal process of an ideal gas is equal to γ.

The correct answer is γ.

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