the ratio of sodium chloride to ammonium in 100 kg of mixed ammonium normally used chloride is 7:25. the amount of sodium chloride to be added to 100kg of mixed to make the ratio 9:25 is
Answers
Step-by-step explanation:
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Given : ratio of sodium chloride to ammonium in 100 kg of mixed ammonium is 7:25
To find : the amount of sodium chloride to be added to 100kg of mixed to make the ratio 9:25
Solution:
ratio of sodium chloride to ammonium in 100 kg of mixed ammonium is 7:25
sodium chloride = (7/(7 + 25)) * 100 = 700/32 = 175/8 kg
ammonium = (25/(7 + 25)) * 100 = 2500/32 = 625/8 kg
amount of sodium chloride to be added = k/8 kg
sodium chloride = 175/8 + k/8 kg = (175 + k)/8 kg
ammonium = 625/8 kg
New ratio is 9: 25
=> (175 + k)/8 : 625/8 = 9 : 25
=> (175 + k)/ 625 = 9/25
=> 175 + k = 225
=> k = 50
amount of sodium chloride to be added = 50/8 = 6.25 kg
amount of sodium chloride to be added = 6.25 kg
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