the ratio of sum of two APs is (2n+1): (2n+5) find ratio of 10th term
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Given ratio of sum of n terms of two AP’s = (2n+1):(2n+5)
Let’s consider the ratio these two AP’s 10th terms as
a10 : a’10 →(2)
Recall the 10th term of AP formula,
an = a + 9d
Hence equation (2) becomes,
a10 : a’10 = a + 9d : a’ + 9d’
On multiplying by 2, we get
a10 : a’10 = [2a + 2*9d] : [2a’ + 2*9d’]
= [2a + 18d] : [2a’ + 18d’]
=( S2) 10th – 1 : (S’2) 10th – 1
= [2(10 )+ 1] : [2(10 )+5] [from (1)]
= 21 : 25
Thus the ratio of 10th terms of two AP’s is
21:25
Given ratio of sum of n terms of two AP’s = (2n+1):(2n+5)
Let’s consider the ratio these two AP’s 10th terms as
a10 : a’10 →(2)
Recall the 10th term of AP formula,
an = a + 9d
Hence equation (2) becomes,
a10 : a’10 = a + 9d : a’ + 9d’
On multiplying by 2, we get
a10 : a’10 = [2a + 2*9d] : [2a’ + 2*9d’]
= [2a + 18d] : [2a’ + 18d’]
=( S2) 10th – 1 : (S’2) 10th – 1
= [2(10 )+ 1] : [2(10 )+5] [from (1)]
= 21 : 25
Thus the ratio of 10th terms of two AP’s is
21:25
shimra44:
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once again thnku sirrr
are u n IITian??
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