the ratio of the age of a and b is 9:4 three years ago the ratio of their age was 3:1 find the present ages
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Let the ages of A and B are x and y respectively
x/y=9/4
4x=9y
x=9y/4............. ( i )
Three years ago,
age of A =x-3
age of B=y-3
A.T.Q
x-3/y-3=3
x-3=3y-9
From( i )
9y/4-3=3y-9
9y-12/4=3y-9
9y-12=12y-36
9y-12y=-36+12
-3y=-24
y=-24/-3
y=8years
Put the value of y in ( i )
x=9×8÷4
×=18years
Present ages of A and B are 18 and 8 respectively
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