Math, asked by vishnuakv000, 2 months ago

The ratio of the age of father and son in a family is 11: 6. If the age of the
mother is added to the age of the son then the ratio becomes 11: 16. If the
age of the son is 30 years, what is the age of the mother?
(a) 25 years (6) 50 years (c) 15 years (d) 45 years​

Answers

Answered by princevg265
0

Answer:

25 years is your answer

Step-by-step explanation:

hope you got it

Answered by SachinGupta01
7

\bf \underline{ \underline{\maltese\:Given} }

 \sf The  \: ratio  \: of  \: the \:  age  \: of \:  father  \: and  \: son \:  in \:  a \:  family \:  is  \: 11: 6

 \sf If \:  the  \: age  \: of \:  the \:  mother \:  is  \: added  \: to \:  the \:  age \:  of \:  the  \: son :

 \sf \implies Then, the \:  ratio \:  becomes \:  11: 16

 \sf  Real  \: age  \: of  \: son = 30  \: years.

\bf \underline{ \underline{\maltese\:To \:  find } }

 \sf \implies Age \:  of  \: mother =  \: ?

\bf \underline{ \underline{\maltese\:Solution } }

 \sf  Let  \: us  \: assume \:  that,

 \sf \implies Age \:  of  \: father \:  be  \: 11x

 \sf \implies Age  \: of \:  son  \: be \:  6x

 \sf \implies Age \:  of  \: mother \:  be \:  y

 \bf \underline{ Now},  \sf according \:  to \:  question,

 \sf  \implies  \bf \dfrac{11x}{6x + y}  =  \dfrac{11}{16}

 \sf  \implies  11(6x + y) = 16(11x)

 \sf  \implies  11(6x + y) = 176x

 \sf  \implies  66x +11y  = 176x

 \sf  \implies  11y  = 176x - 66x

 \sf  \implies  11y  = 110x

 \sf  \implies y  = \cancel  \dfrac{110x}{11}

 \sf  \implies y  = 10x

 \bf \underline{ Now},

 \sf Since,  age  \: of  \: son  \: is \:  30 \:  years.

 \sf  \implies 6x = 30

 \sf  \implies x =  \cancel \dfrac{30 }{6}

 \sf  \implies x = 5

 \bf \underline{ Therefore},

 \sf \implies  Age  \: of \:  mother  \: (y) =  \bf 10(x) = 10 \times5= 50 \: years

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