Math, asked by rajumiah37881, 6 months ago

the ratio of the age of father is 2:1 10years ago the ratio becomes 5:2 find the ages​

Answers

Answered by Darshini1318
2

Here your answer.

Hope this is helpful.........

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Answered by thameshwarp9oqwi
1

Answer:

let, father is two time greater than his son

ratio of father = 2x

ratio of son = x

10 year ago

ratio of father = 5x

and ratio of son = 2x

ten year ago

(2x-10)/(x-10) = 5/2

==> 4x-20 = 5x-50

==> -x = -30

==> x = 30

so, 2x = 2(30) ==> 60

answer = 30 and 60

father age = 60 and son age = 30

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