Question

The ratio of the age of paul and the sum of ages of his two sons 6:1

Answer 1

Sons’s age = Y * T(a-b) / difference of cross product

Or 1 * 5 (6-1) / 12 – 7

5*5 / 5 = 5 yrs

Father’s age = X *T (a-b) / Difference of cross product

6*5 (6-1) / 12-7

=6*5 = 30 yrs

Answer 2

Given:

Sum of the ratio of the ages of two sons is 6:1

To Find:

the age of two sons

Solution:

Let the age of one son be 'a' and the age of other son is 'b'

Son's age = Y × T(a-b)/difference of cross product

                 = 1 × 5(6 - 1)/12 - 7

                 = 5 × 5/5

                 = 25/5

                 = 5 years

so, the age of his son is 5 years.

Father's age = X × T(a-b)/difference of the cross product

                     = 6 × 5(6-1)/12 - 7

                     = 5.5 years

Therefore, the age of the sons is 5 years and 5.5 years.