Question

the ratio of the ages of A AND B is 1 is to 2 after 7 years the ratio of the ages are 3 is to 5 find the find the age 7 years ago​

Answer 1

The ratio of the ages of A and B is 1:2.

Let us assume that the A is 1M years and B as 2M years.

After 7 years the ratio of the ages are 3:5.

After 7 years,

• Age of A = (1M + 7) years
• Age of B = (2M + 7) years

According to question,

⇒ (M + 7)/(2M + 7) = 3/5

Cross-multiply them

⇒ 5(M + 7) = 3(2M + 7)

⇒ 5M + 35 = 6M + 21

⇒ 5M - 6M = 21 - 35

⇒ - M = - 14

⇒ M = 14

Therefore,

Present age of A = M = 14 years

Present age of B = 2M = 28 years

But we have to find the ages of A and B; 7 years ago.

So,

Age of A, 7 years ago = 14 - 7 = 7 years

Age of B, 7 years ago = 28 - 7 = 21 years

Answer 2

Answer:

Step-by-step explanation:

Solution :-

Given Ratios of ages of A and B = 1 : 2

Let the age of A be 1x years and B be 2x years.

After 7 years the ratio of the ages are 3 : 5.

Then, Age of A = x + 7 and Age of B = 2x + 7

As per the Question,

⇒ (x + 7)/(2x + 7) = 3/5

⇒ 5(x + 7) = 3(2x + 7)

⇒ 5x + 35 = 6x + 21

⇒ 5x - 6x = 21 - 35

⇒ - x = - 14

⇒ x = 14

Present Age of A = x = 14 years

Present Age of B = 2x = 28 years

Now, Finding the age 7 years ago​,

Age of A = 14 - 7 = 7 years

Age of B = 28 - 7 = 21 years

Thus, the age 7 years ago​ of A and B is 7 and 21 years.