Question

The ratio of the ages of a father and son is 17 : 7. 6 years ago the ratio of the ages was three ratio one the father's present age is

Answer 1

Answer:

Age of , father : son =17:7

Let age of father = 17x and 7x

Six years ago ages was 17x-6 and 7x-6 , and the ratio was 3:1

So, (17x-6)/(7x-6)=3:1

So, 3(7x-6)=1(17x-6)

Or, 21x-18=17x-6

Or, 21x-17x =18–6

Or, 4x=12

Or, x=12/4=3

Present age of father =17×3=51

Present age of son = 7×3=21

Step-by-step explanation:

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Answer 2

Answer:

Thanks for your question...

Your required answer :

• Ratio of father and son= 17 : 7
• Let the present age of father be = 17x
• Let the present age of son be = 7x

Now 6 years ago :

• Father's age = 17x - 6
• Son's age = 7x - 6

----→ Their ratio = 1 : 3

Now solving :

• ( 17x - 6 ) / ( 7x - 6 ) = 3 / 1

By cross multiplication :

• 3 ( 7x - 6 ) = 1 ( 17x - 6 )
• 21x - 18 = 17x - 6
• 21x - 17 x = -6 + 18
• 4x = 12
• x = 3

Now by putting the value of x :

→ Present age of father = 17 ( 3 ) = 51 years

→ Present age of son = 7 ( 3 ) = 21 years

Brainliest Please