Math, asked by tammiclick, 9 months ago

The ratio of the ages of a girl and her mother is 1:3. After 6 years, the ratio will be 5:12. If the present ages are x and 3x, find the ages after 6 years.

Answers

Answered by revanthsenthilp30d0w
35

Answer:

Girl's age : 20

Mother's age : 48

Step-by-step explanation:

It is given that the ratio is 1:3, and the current ages are also given (because of the ratio) as x and 3x. We also know for a fact that after 6 years, their respective ages are in the ratio 5:12.

So, we can write the following equation:

\frac{x+6}{3x+6} = \frac{5}{12}  \\

The above relation is because of their respective ratios.

Solving the same,

(x + 6) * 12 = (3x + 6) * 5\\12x +72 = 15x + 30\\42 = 3x\\

Hence, x = 14

But we need to find their respective ages after 6 years:

Girl's age after 6 years : 14 + 6 = 20

Mother's age after 6 years : (3*14) + 6 = 42 + 6 = 48

Answered by Anonymous
68

Answer -

Age of girl after 6 years = 20 years

Age of mother after 6 years = 48 years

Step-by-step explanation -

\bold{\sf{\green{Method\:1)}}}

The ratio of the ages of a girl and her mother is 1:3.

Let present age of girl be 1M and present age of mother be 3M.

After 6 years, the ratio will be 5:12.

After 6 years, age of girl will be 1M + 6 and mother will be 3M + 6 and ratio of their ages after 6 years, will be 5:12.

\implies\:\sf{\dfrac{1M\:+\:6}{3M\:+\:6}\:=\:\dfrac{5}{12}}

\implies\:\sf{12(M\:+\:6)\:=\:5(3M\:+\:6)}

\implies\:\sf{12M\:+\:72\:=\:15M\:+\:30}

\implies\:\sf{12M\:-\:15M\:=\:30\:-\:72}

\implies\:\sf{-3M\:=\:-42}

\implies\:\sf{M\:=\:14}

\therefore Age of girl after 6 years = \sf{1(14)\:+\:6}

=> \sf{14\:+\:6}

=> \sf{20\:years}

\therefore Age of mother after 6 years = \sf{3(14)\:+\:6}

=> \sf{42\:+\:6}

=> \sf{48\:years}

\rule{200}2

\bold{\sf{\green{Method\:2)}}}

The ratio of the ages of a girl and her mother is 1:3.

Let age of girl be 'G' and age of mother be 'M'

\implies\:\sf{\dfrac{G}{M}\:=\:\dfrac{1}{3}}

\implies\:\sf{G\:=\:\dfrac{M}{3}} ...(1)

After 6 years, the ratio will be 5:12.

\implies\:\sf{\dfrac{G\:+\:6}{M\:+\:6}\:=\:\dfrac{5}{12}}

\implies\:\sf{12(G\:+\:6)\:=\:5(M\:+\:6)}

\implies\:\sf{12G\:+\:72\:=\:5M\:+\:30}

\implies\:\sf{12G\:-\:5M\:=\:30\:-\:72}

\implies\:\sf{12(\frac{M}{3})\:-\:5M\:=\:-42}

\implies\:\sf{\frac{12M\:-\:15M}{3}\:=\:-42}

\implies\:\sf{-3M\:=\:3(-42)}

\implies\:\sf{M\:=\:42}

Substitute value of M in equation (1)

\implies\:\sf{G\:=\:\dfrac{42}{3}}

\implies\:\sf{G\:=\:14}

\therefore Age of girl after 6 years = \sf{14\:+\:6}

=> \sf{20\:years}

\therefore Age of mother after 6 years = \sf{42\:+\:6}

=> \sf{48\:years}

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