Question

The ratio of the ages of Anthony and Amar is 6:7 .Albert is 4 years older than Amar. Find the age of Albert, if the sum of their ages is 1 year more than thrice the age Amar. ..

Answer 1

age of anthony=6x
age of amar=7x
age of albert=4+7x
sum of ages
6x+7x+(4+7x)=1+3(7x)
13x+7x+4=1+21x
20x+4=1+21x
-1x=-3
(-)&(-) cancel
1x or x = 3
we've to find the age of Albert
so,4+7(3)
4+21=25
Albert is 25years old...


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Answer 2

Anthony:Amar = 6:7....(i)
Albert = 4 + Amar.......(ii)

Albert + Anthony + Amar = 1 + 3*Amar.....(iii)
(ii) in (iii)

4 + Amar + Anthony + Amar = 1 + 3Amar
3 + Anthony = 3Amar - 2Amar = Amar
Amar = 3 + Anthony....(iv)
From (i): Anthony/Amar = 6/7
Anthony/3 + Anthony = 6/7
7 Anthony = 18 + 6 Anthony
Anthony = 18 years..
Amar = 18+3 = 21 years
Albert = 4 + Amar = 4 + 21 = 25 years
Hence age of Albert = 25 years.
Hope it helps.