Question

the ratio of the ages of father and daughter is 4:1. 10 years ago the sum of their ages was 40 what is the present age of daughter ​

Answer 1

Answer:

Daughter's age = 12 years

Step-by-step explanation:

let the ages be 4x and 1x

Father = 4x

daughter = 1x

10 years ago :

Father = 4x - 10

daughter = 1x - 10

Sum of their ages :

$\implies$ $(4x-10)+(1x-10)=40$

$\implies$ $4x-10+1x-10=40$

$\implies$ $5x-20=40$

$\implies$ $5x=60$

$\implies$ $x={\Large\frac{60}{5}}$

$\implies$ $\boxed{x=12}$

Father's age = 4x = 4(12) = 48 years

Daughter's age = x = 12 years

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