Math, asked by santoshkewat53324, 10 months ago

the ratio of the ages of Hina and Kanika is 4 ratio 3. the sum of their ages is 28 find the age of Heena
options
a)15 years
b)12 years
c)16 years
d)18 years​

Answers

Answered by shivamk21784
1

Answer:

4x+3x=28 then 7x=28 x= 4 heena age= 4×4=16

Answered by Anonymous
4

Answer:

The ratio of the ages of Hina and Kanika is 4 ratio 3. the sum of their ages is 28 find the age of Heena,

a)15 years

b)12 years

c)16 years✔️

d)18 years

Step-by-step explanation:

Let the age of Hina be 4x.

And, the age of Kanika be 3x.

Given sum of ages = 28.

So, according to the question

4x+3x = 28

7x = 28

x = 28/7 = 4.

As x is equal to 4, so age of Hina is 4x=4×4=16 years and age of Kanika is 3×4= 12years.

Therefore, Hina's age is 16 years and Kanika's age is 12 years respectively.

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