Math, asked by sanaqureshi10, 1 year ago

The ratio of the ages of man and his wife is 4:3. After 4 years, the ration will be 9:7. If at the time of marriage, the ratio was 5:3, how many years ago were they married?


sanaqureshi10: may i have the solution ?

Answers

Answered by Chetanjain004
0
You can see an example sum and do it
Answered by llTheUnkownStarll
2

Given:

  • The ratio of the ages of a man and his wife is 4:3
  • After 4 years, the ratio will be 9:7
  • Time of marriage, the ratio was 5:3

To find:

  • Years ago they married?

Solution:

✪ Let us consider the Present age of man and his wife be 4x and 3x respectively.

Then, After 4 years,⠀⠀⠀⠀

  • Husband's age = (4x + 4) years
  • Wife's age = (3x + 4) years

\begin{gathered}\underline{\boldsymbol{ \textsf{ \textbf{According\:to \:the \:given \:Condition,}}}}\\\end{gathered}

  • After 4 years, The ratio of the age of a man and his wife will be 9:7.

⠀⠀⠀⠀⠀

\begin{gathered}:\implies\sf \dfrac{4x + 4}{3x + 4} = \dfrac{9}{7}\\\\\\ :\implies\sf 7(4x + 4) = 9(3x + 4)\\\\\\ :\implies\sf 28x + 28 = 27x + 36\\\\\\ :\implies\sf 28x - 27x = 36 - 28\\\\\\ :\implies{\underline{\boxed{\frak{{x = 8}}}}}\blue\bigstar\\\\\end{gathered}

Therefore,

  • The Present age of Man, 4x = 4×8 = 32 years
  • And, The Present age of his wife, 3x = 3×8 = 24years

✪ Now, Lets assume that their marriage took place in "T years" back.

⠀⠀⠀⠀

Then, By given Condition,

  • The ratio of the age of a man and his wife at the time of marriage is 5:3.

 \begin{gathered}:\implies\sf \dfrac{32 - T}{24 - T} = \dfrac{5}{3}\\\\\\ :\implies\sf 3(32 - T) = 5(24 - T)\\\\\\ :\implies\sf 96 - 3T = 120 - 5T\\\\\\ :\implies\sf 5T - 3T = 120 - 96\\\\\\:\implies\sf 2T = 24\\\\\\:\implies\sf T = \cancel{\dfrac{24}{2}}\\\\\\ :\implies{\underline{\boxed{\frak{{T = 12\:years}}}}}\pink\bigstar\\\\\end{gathered} \\  \\ \therefore\:{\underline{\sf{Hence,{They\:were\:married}\:\pmb{12\:years}\:\sf{ago}.}}}

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