Math, asked by ru1t1hiaevakoushas, 1 year ago

The ratio of the ages of sameer and akhiltwo years ago was 2:3 four years from now the ratio of the ages will be 3:4 find their present age

Answers

Answered by noorpreet20
8

Step-by-step explanation:

Let the present ages of Sameer and Akhil is x and you respectively. The ratio of the ages of Sameer and Akhil was 2:3 two years ago

Then,

x-2/y-2=2/3

or, 3x-6 = 2y-4

or, 3x-2y = -4+6

or, 3x-2y = 2...........(1)

Four years later from now the ratio of their ages will be 3:4

Then,

x+4/y+4 = 3/4

or, 4x+16 = 3y+12

or, 4x-3y = 12-6

or, 4x-3y = -4..........(2)

Multiply (1) with 4 and (2) with 3 we get,

12x-8y = 8.............(3)

12x-9y = -12..............(4)

Subtracting (4) from (3)

y = 20

3x = 2+2y

or, 3x = 2+2×20

or, 3x = 2+40

or, x = 42/3

or, x = 14

therefore, present ages of Sameer and Akhil are 14 years and 20 years respectively.

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