The ratio of the ages of two sisters is 2:3. Six years later, the ratio of their ages will be 3:4. Find their present ages
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Answered by
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The present age of one sister is 12years and the present age of the second sister is 18 years.
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skandh7:
can you write it in detail
Answered by
17
we have the ratio of two ages ie, 2:3.
So let the common factor of their ages be x.
So their ages are 2x and 3x.
6 years later their ages will be 3:4.
ATQ,
2x+6. 3
____=. _
3x+6. 4
Cross multiplying we get,
3(3x+6)=4(2x+6)
9x+18=8x+24
9x-8x=24-18
x=6,
Hence,
Their present ages will be,
2*6=12
3*6=18
______________________
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So let the common factor of their ages be x.
So their ages are 2x and 3x.
6 years later their ages will be 3:4.
ATQ,
2x+6. 3
____=. _
3x+6. 4
Cross multiplying we get,
3(3x+6)=4(2x+6)
9x+18=8x+24
9x-8x=24-18
x=6,
Hence,
Their present ages will be,
2*6=12
3*6=18
______________________
Please mark my answer as brainliest it it's correct and helped you.
Thanks;)
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