Question

the ratio of the ages of two sisters is 3:7.In ten years ,the ratio of their ages becomes 2:3 .Find their present ages.

Answer 1

one is-6 and other 14

Answer 2

at present two sisters ages are 3x and 7x

after ten years their ages are 3x+10 and 7x+10

(3x+10)/(7x+10) = 2/3 given

3(3x+10) = 2(7x+10)

9x+30=14x+20

30-20 =14x-9x

10 =5x
5x= 10
x= 10/5

x= 2

present ages are 3x=3*2 =6years
and 7x= 7*2 = 14 years