the ratio of the ages of two sisters is 3:7.In ten years ,the ratio of their ages becomes 2:3 .Find their present ages.
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one is-6 and other 14
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at present two sisters ages are 3x and 7x
after ten years their ages are 3x+10 and 7x+10
(3x+10)/(7x+10) = 2/3 given
3(3x+10) = 2(7x+10)
9x+30=14x+20
30-20 =14x-9x
10 =5x
5x= 10
x= 10/5
x= 2
present ages are 3x=3*2 =6years
and 7x= 7*2 = 14 years
after ten years their ages are 3x+10 and 7x+10
(3x+10)/(7x+10) = 2/3 given
3(3x+10) = 2(7x+10)
9x+30=14x+20
30-20 =14x-9x
10 =5x
5x= 10
x= 10/5
x= 2
present ages are 3x=3*2 =6years
and 7x= 7*2 = 14 years
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