The ratio of the area of the rectangle and square is 8:9. If the perimeter of each is 24 cm find the dimensions of the rectangle
Answers
Answered by
12
Hey.
Here is the answer.
let side of square be a
so, perimeter = 4 a = 24 cm
so, side, a = 6 cm
So, area = a^2 = 6^2 = 36 cm^2 b
As, ratio of areas is 8 : 9
so, area of rectangle/ area of square = 8 / 9
or, area of rectangle / 36 = 8/9
or, area of rectangle = 8×36/9 =32 cm^2
so, l×b = 32
or, l = 32/b
As, 2( l + b) = 24______ perimeter
or, 2( 32/b + b ) = 24
or, 32 + b^2 = 12 b
or, b^2 - 12 b = 32
or, b^2 -12b + 36 = 32 + 36
or, ( b - 6)^2 = 68
or, b - 6 = 8.246
or, b = 2.246 cm
So, l = 32/2.246 = 14.247 cm
Thanks .
Here is the answer.
let side of square be a
so, perimeter = 4 a = 24 cm
so, side, a = 6 cm
So, area = a^2 = 6^2 = 36 cm^2 b
As, ratio of areas is 8 : 9
so, area of rectangle/ area of square = 8 / 9
or, area of rectangle / 36 = 8/9
or, area of rectangle = 8×36/9 =32 cm^2
so, l×b = 32
or, l = 32/b
As, 2( l + b) = 24______ perimeter
or, 2( 32/b + b ) = 24
or, 32 + b^2 = 12 b
or, b^2 - 12 b = 32
or, b^2 -12b + 36 = 32 + 36
or, ( b - 6)^2 = 68
or, b - 6 = 8.246
or, b = 2.246 cm
So, l = 32/2.246 = 14.247 cm
Thanks .
Similar questions