The ratio of the areas of a rectangle to a square is 8:9. If the perimeter of each of them is 48cm, then find the dimensions of the rectangle. please give a detailed and quick answer!!
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The perimeter of square is given that
48 cm and rectangle is 48 cm
4s = 48
S=12 = side
Let the quantity in ratio be x
So
8x=area of rectangle
9x=area of square = 12*12=144
X=16
So area of rectangle will be 8 *16
128
Lb=128
2l+2b=48
B=128/l
2*128/l +2*l=48
256/l+2l=48
256+2lsq/l=48
256+2lsq=48 L
(128+Lsq)=24l
Lsq=24l-128
48 cm and rectangle is 48 cm
4s = 48
S=12 = side
Let the quantity in ratio be x
So
8x=area of rectangle
9x=area of square = 12*12=144
X=16
So area of rectangle will be 8 *16
128
Lb=128
2l+2b=48
B=128/l
2*128/l +2*l=48
256/l+2l=48
256+2lsq/l=48
256+2lsq=48 L
(128+Lsq)=24l
Lsq=24l-128
nishartk2007p9sdlo:
how you find the area of rectangle=8*16 .........plzzzzzzz explain
So area of rectangle will be 8 *16
128
Lb=128
2l+2b=48
B=128/l
2*128/l +2*l=48
256/l+2l=48
256+2lsq/l=48
256+2lsq=48 L
(128+Lsq)=24l
Lsq=24l-128
128
Lb=128
2l+2b=48
B=128/l
2*128/l +2*l=48
256/l+2l=48
256+2lsq/l=48
256+2lsq=48 L
(128+Lsq)=24l
Lsq=24l-128
these steps are not clear to me!!!!
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