The ratio of the areas of a rectangle to a square is 8:9. If the perimeter of each of them is 48cm, then find the dimensions of the rectangle. please give a detailed and quick answer!! please solve on a paper it's a humble request
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Answered by
41
Dimensions of the square:
For a square of side x, perimeter = 4x
4x = 48
x = 12 cm
Area of square = 12x12 = 144
The ratio of the areas of a rectangle to a square is 8:9.
Area of rectangle: Area of square = 8:9
Area of rectangle:144 = 8:9
Area of rectangle/144 = 8/9
Area of rectangle = 144(8/9) = 128 cm^2
If the rectangle has dimensions of a, b
Area = ab = 128 -------- (i)
Perimeter = 2(a + b) = 48
a + b = 24 -------- (ii)
From (i), b = 128/a
Substitute in (ii)
a + b = 24
a + 128/a = 24
a^2 – 24a + 128 = 0
a^2 – 8a – 16a + 128 = 0
a(a – 8) -16(a – 8) = 0
(a – 16)(a – 8) = 0
Either a = 8 or a = 16
When a = 8, b = 16 and when a = 16, b = 8
Therefore the dimensions of the rectangle are:
8 cm by 16 cm
For a square of side x, perimeter = 4x
4x = 48
x = 12 cm
Area of square = 12x12 = 144
The ratio of the areas of a rectangle to a square is 8:9.
Area of rectangle: Area of square = 8:9
Area of rectangle:144 = 8:9
Area of rectangle/144 = 8/9
Area of rectangle = 144(8/9) = 128 cm^2
If the rectangle has dimensions of a, b
Area = ab = 128 -------- (i)
Perimeter = 2(a + b) = 48
a + b = 24 -------- (ii)
From (i), b = 128/a
Substitute in (ii)
a + b = 24
a + 128/a = 24
a^2 – 24a + 128 = 0
a^2 – 8a – 16a + 128 = 0
a(a – 8) -16(a – 8) = 0
(a – 16)(a – 8) = 0
Either a = 8 or a = 16
When a = 8, b = 16 and when a = 16, b = 8
Therefore the dimensions of the rectangle are:
8 cm by 16 cm
Answered by
5
Answer:
8 cm and 16 cm
Step-by-step explanation:
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