The ratio of the areas of a square and a regular hexagon with inscribed in a circle is
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Let the radius of the circle = r
Then the diameter of the circle = the diagonal of the square = 2r
Let a side of the square = x
Then 2x^2 = (2r)^2 = 4r^2
The area of the square = x^2 = 2r^2
The hexagon can be partitioned into 6 equilateral triangles whose sides = r
If the sides of an equilateral triangle = r then its area = r^2 (sqrt 3)/4
So the area of the hexagon = 6 r^2 (sqrt 3)/4 = 3 r^2 (sqrt 3)/2
Thus the ratio of the area of the square to that of the hexagon =
2r^2/[3 r^2 (sqrt 3)/2]
= 4/(3 sqrt 3)
= approx. 0.7698
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