the ratio of the areas of a square of side a and that of an equilateral triangle of side a is
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Step-by-step explanation:
Area of square = s^2
Area of trainge = 1/2*t* {(sqt3)/4}t
1/2*t* {(sqt3)/4}t = s^2
t^2/S^2 = 4/sqt3
t/s = 2/4rt 3
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(a^2)/(√3a/4)
4a/√3 is the answer
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4a/√3 is the answer
hope you like it
mark me brainliest
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