Question

The ratio of the areas of two circles is 1 : 9 then ratio of their circumferences is​

Answer 1

Answer:

$let \: radius\: of \: first \: circle =x \\ let \: radius \: of \: second \: circle \: = y \\ then \: area \: of \: first \: circle \: = \pi {x}^{2} \\ and \: area \: of \: second \: circle \: = \pi {y}^{2} \\ it \: is \: given \: that \: \frac{\pi {x}^{2} }{\pi {y}^{2} } = \frac{1}{9} \\ soving \: it \: \: \: \: \: \frac{\pi {x}^{2} }{\pi {y}^{2} } = \frac{1}{9} \\ \frac{ {x}^{2} }{ {y}^{2} } = \frac{ {1}^{2} }{ {3}^{2} } \\ \\ so \: now \: ratio \: of \: their \: circumference \: will \: be \: = \frac{2\pi \times x}{2\pi \times y} \\ = \frac{x}{y} \\ which \: is \: equal \: to \: \frac{1}{3}$

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