CBSE BOARD X, asked by dineshkumarmahanta1, 1 month ago

The ratio of the areas of two similar triangles is equal to the square of ratio of their corresponding angle bisectors​

Answers

Answered by uratnakar1980
0

Answer:

The ratio of the area of two similar triangles is equal to the square of the ratio of any pair of the corresponding sides of the similar triangles. For example, for any two similar triangles ΔABC and ΔDEF, Area of ΔABC/Area of ΔDEF = (AB)2/(DE)2 = (BC)2/(EF)2 = (AC)2(DF)2.

Answered by saiaksharavadla
0

Answer:

The ratio of the areas of two similar triangles is equal to the square of ratio of their corresponding angle bisectors

sorry for this question I don't know the answer

I am Sai Akshara

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