Question

The ratio of the areas of two squares is 4:9. The ratio of their perimeters in the same order

Answer 1

Answer:

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Answer 2

The ratio of their perimeters in the same order is 2:3

Step-by-step explanation:

Let the side of squares be x and y

So, Area of square =$Side^2$

Area of first square = x^2

Area of second square  = y^2

We are given that The ratio of the areas of two squares is 4:9

So,$\frac{x^2}{y^2}=\frac{4}{9}\\\frac{x}{y}=\sqrt{\frac{4}{9}}\\\frac{x}{y}=\frac{2}{3}$

So, The ratio of the sides of square are 2:3

Let the ratio be x

So, Sides of square are 2z and 3z

So, Perimeter of square = $4 \times Side$

Perimeter of square 1 = $4 \times 2z$

Perimeter of square 2 = $4 \times 3z$

Ratio of perimeter of squares = $\frac{4 \times 2z}{4 \times 3z}=\frac{2}{3}$

Hence The ratio of their perimeters in the same order is 2:3

#Learn more:

If the perimeter of a circle is equal to the perimeter of square, then find the ratio of their area​

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