Question

the ratio of the areas of two squares one having its diagonal double that of the other is ​

Answer 1

Answer:

1:4

Step-by-step explanation:

Diagonal of square of side S is √2×S

Let the length of the small diagonal be X

then, the length of the larger diagonal is 2X

Let the length of the side of the small square be Q

√2×Q=X

Q=X÷√2

=(√2×X)/2

Area of square of side Q=Q²=X²÷4

Let the length of the side of the big square be W

W×√2=2X

W=2X÷√2

=√2×X

Area of square of side W=W²=1÷2X²

Q²:W²=1:4