Question

the ratio of the areas of two squares one having its diagonal double that of the Other what is this find the ratio

Answer 1

QUESTION


the ratio of the areas of two squares one having its diagonal double that of the Other what is this find the ratio



SQUARE

Whose all side are Equal and adjacent side made 90° angle


AREA OF SQUARE IN TERM OF DIAGONALS



$area = \frac{1}{2} {d}^{2}$


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=>HOW THIS REALATION OCCUR


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BACK ON QUESTION



Let area of ist square =A


area of 2nd square = B


Diagonal of first square = d


Diagonal of 2nd square =2d



SO,


Area of ist square

$= \frac{1}{2} {d}^{2}$




Area of 2nd square


=
$= \frac{1}{2} {(2d)}^{2}$

RATIO





$\frac{area \: \: of \: first \: square \: }{area \: of \: 2n d \: square}$







$\frac{ \frac{1}{2} {d}^{2} }{ \frac{1}{2} {(2d)}^{2} }$






$= \frac{1}{4}$