The ratio of the areas of two triangles A1: A2 is
3:2. The corresponding bases are b1 and b2. The
heights of the triangles are equal. If b2 = 12 cm.
Find b1.
Answers
Answer:
18cm
Step-by-step explanation:
For detailed solution view attachment.
The length of base of 1st triangle is 18cm.
The ratio of the areas of two triangles A₁ : A₂ is 3 : 2. The corresponding bases are b₁ and b₂ and heights of the triangles are equal.
We have to find the value of b₁ , if b₂ = 12 cm.
We know, the area of triangle = 1/2 × base × height
∴ the area of first triangle, A₁ = 1/2 × b₁ × h₁
And the area of 2nd triangle, A₂ = 1/2 × b₂ × h₂
A/C to question,
- A₁ : A₂ = 3 : 2
- h₁ = h₂ [ heights of triangles are equal ]
- b₂ = 12 cm
∴ A₁/A₂ = (1/2 × b₁ × h₁)/(1/2 × b₂ × h₂) = (b₁/b₂) × (h₁/h₂)
⇒ 3/2 = b₁/12 × 1/1
⇒ b₁ = 18 cm
Therefore the length of base of 1st triangle is 18cm.
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