The ratio of the areas of two triangles with
common base is 4: 3. Height of the larger
triangle is 6 cm, then find the corresponding
height of the smaller triangle.
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Given:
- We have been given that area of two triangles having a common base is in the ratio 4:3
- Height of larger Triangle is 6 cm
To Find:
- We have to find the corresponding height of smaller triangle
Construction:
- Dropping a perpendicular from A on Base BC which intersect at point M
- Dropping a perpendicular from D on Base BC which intersect at N
Solution:
Let the larger triangle be = Δ ABC
Smaller Triangle be = Δ BCD
Both Triangles having a Common Base
Dropping a perpendicular from Point A on Base BC which represents Height of Δ ABC
Similarly
Dropping a perpendicular from Point D on Base BC which represents Height of Δ BCD
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The area of triangles are in the ratio 4:3
Putting Value of AM = 6 cm
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- A triangle is a three sided figure , having three vertices and angles
- The sum of interior angles of triangle is always 180
- The sum of length of two sides of a triangle is a always greater than the third side
- Triangle can be classified in basically three types :
- Equilateral Triangle : Having all Equal sides and angles
- Isosceles Triangle : Having two sides and two angles Equal
- Scalene Triangle : Having All ths sides and angles different
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