Math, asked by ranveerkadam2000, 7 hours ago

The ratio of the areas of two triangles with the common base is 6: 5. Height of the larger triangle is 9 cm. Then find the corresponding height of the smaller triangle.

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Answers

Answered by anaghasethu1998
4

Step-by-step explanation:

Area of triangle = bh/2

Where b = base and

h = height

It's given

Ratio of areas = 6 : 5

b1=b2=b

h1 = 9

h2 = h

(b1h1/2) / (b2h2/2)

b1h1 /b2h2

b9 / bh = 6 : 5

9 / h = 6 / 5

h = 9 * 5 / 6 = 15/2

h = 7.5

Answered by raimanju1176
2

Step-by-step explanation:

Let the areas of the larger and the smaller triangle be A1 and A2 respectively. Let their heights be h1 and h2 respectively.

Given A2A1=56,h1=9 and the two triangles have the common base.

∴A2A1=h2h1

⇒56=h29

⇒h2=645

⇒h2=7.5cm

Thus the height of the smaller triangle is 7.5cm

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