Question

The ratio of the arms of two duplicate triangles to 4: 9 then what is the area of the two trangle
1/2:3
2/4:9
3/81:16
4/16:81

Answer 1

$\dfrac{\text{Area 1}}{\text {Area 2}} = \bigg( \dfrac{\text{Length 1}}{\text {Length 2}} \bigg)^2$

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$\dfrac{\text{Area 1}}{\text {Area 2}} = \bigg( \dfrac{\text{4}}{\text {9}} \bigg)^2 = \dfrac{16}{81}$

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Answer: (4) 16/81