Math, asked by sekhon94, 1 year ago

the ratio of the base to that of altitude of a parallelogram is 1 ratio 3 if the area of the parallelogram is 48 CM square the base and the altitude respectively

Answers

Answered by ReethuJJ
0
Area of parrallelogram=b×h
b=1x
h=3x
area=48
1x×3x=48
4x=48cm
x=48÷4
=22
there fore base= 1×25
=22
height=3×22
=66
Answered by Anonymous
0

Given - Ratio of base to altitude

Find - Base and altitude

Solution - Let the base and altitude of parallelogram be x.

Length of base and altitude will be 1x and 3x.

Area of parallelogram = base * height

Area of parallelogram = 1x*3x

48 = 3x²

 {x}^{2}  =  \frac{48}{3}

 {x}^{2}  = 16

x =  \sqrt[2]{16}

x = 4

So, base of parallelogram = 1x

Base of parallelogram = 1*4

Base of parallelogram = 4 centimetres

Altitude of parallelogram = 3x

Altitude of parallelogram = 3*4

Altitude of parallelogram = 12 centimetres

So, the base and altitude of parallelogram are 4 and 12 centimetres respectively.

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