Question

The ratio of the base to the height of a parallelogram is 4:3. If the area of the parallelogram is 5292 cm ^ 2 find its base and height.​

Answer 1

$\huge{ \color{purple} \colorbox{pink}{answer}}$

let base = 4x

let height = 3x

$\large \green{ \star{area \: of \: parallelogram = 3468}}$

$\large{ \pink{ \fbox{ area = bxh}}}$

3468cm= 4x × 3x

3468 = 12x

$\frac{3468}{12} = x$

$x = 289$

$\large{ \purple{ \star \: {take \: square \: root}}}$

$x = 17$

$\large{ \underline{height}{ = 3x = 3 \times 17 = 51}}$

$\large{ \underline{base}{ = 4x = 4 \times 17 = 68}}$

hope its help u

Answer 2

Answer:

Base and height of parallelogram are $84$ cm and $63$ cm  respectively .

Step-by-step explanation:

To find : base and height of parallelogram .

Given : the ratio of the base to the height of a parallelogram is $4:3$ and area of the parallelogram is $5292\ cm ^ 2$ .  

Solution:

• As per the given data we know that the ratio of the base to the height of a parallelogram is $4:3$ and area of the parallelogram is $5292\ cm ^ 2$ .
• Let base and height of parallelogram be $4x$ and $3x$ respectively .  
• To find base and height of parallelogram we use formula of area of parallelogram.
• Area of parallelogram = $base \times height$

        $5292 = 4x \times 3x \\\\ 5292 = 12x^{2} \\\\ x^{2} = \frac{5292}{12}\\\\ x^{2} = 441\\\\\sqrt{x^{2} } = \sqrt{441} \\\\ x= 21$

• Now , substituting value of $x$ in  $4x$ and $3x$ to find base and height respectively .  
• Base = $4x =4 \times 21= 84\ cm$
• Height = $3x = 3\times 21 = 63\ cm$