The ratio of the corresponding sides of the similar triangles is 7:5, then find
ratio of the areas of the triangle ?
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Hey mate here is your answer
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here the answer will be the square of the given ratios......as:
Step-by-step explanation:
now let us consider sides as AB and PQ
hence they are corresponding their angles are to corresponding
now to find area of ∆'s we have to
area (∆ABC)=[AB]^2
area (∆PQR) [PQ]^2
now substitute the value of AB and PQ
therefore,
area(∆ABC)/area(∆PQR)=(5/7)^2
i.e.25/49
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